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Interpreting nutrient analysis

How to read nutrient label analyses (i.e. “Guaranteed Analysis”)

With the common exception of potassium and phosphorus, most nutrient labels state the concentration of nutrient species in their elemental form – as per the “Element” column in Chart 1.

K2O and P2O5:  By convention, many labels represent potassium (K) as dipotassium oxide (K2O).  To convert K2O to K, multiply the K2O figure by 0.83.  Similarly, phosphorus (P) is often represented as phosphorus pentoxide (P2O5).  To convert P2O5 to P, multiply the P2O5 figure by 0.44.

Concentration:  The concentration of elements are represented in percentage (%).  Specifically this is %m/v (i.e. percentage mass per unit of volume).  Multiplying this figure by 10 derives the concentration in grams per litre e.g. 3.0% equals 30g/L.  Alternatively, multiplication by 10,000 derives the concentration in ppm or mg/L e.g. 3.0% equals 30,000ppm.

 

How to compare nutrient label analyses of 1, 2 & 3-part labels

Label analysis figures for 2 & 3-part nutrients are usually based upon the concentration of nutrients in the individual packs.  Therefore, for example, in order to make a meaningful comparison between a 2-part and 1-part nutrient, it is necessary to first double the figures quoted on the 1-part.  This ensures we are comparing the contents of equal volumes e.g. 2 x 1L bottles of the 1-part with 2 x 1L bottles (’A’ and ‘B’) of the 2-part. 

Obviously, to compare a 1-part with a 3-part, we would firstly ‘triple’ the 1-part figures.  Further, to compare a 2-part with a 3-part, we must first halve the 2-part figures before multiplying them by 3.

Using this information we are able to compare analyses.  For instance, in Graph 3.1 we are able to make a meaningful comparison between a 1, 2 and 3-part nutrient. 

 

Concentration of specific nutrient elements yielded by a given dose

To determine this, the individual analysis specification should first be converted into ppm (or mg/L), then multiplied by the dose rate (per litre).  For example, if part ‘B’ of a 2-part, contains 3.0% phosphate as P2O5, then when this part is used at 4ml per litre, it will yield 53ppm phosphorus as P.  That is: 

Step 1.  “3.0% P2O5” = 30,000ppm as P2O5 (i.e. 3.0% x 10,000).

Step 2.  Convert this figure to P:  30,000ppm as P2O5 =  13,200ppm as P (30,000ppm x 0.44).

Step 3.  4ml per litre yields 53ppm P (i.e. 13,200ppm x 4ml /1,000ml).

 

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